Hello, using baanIVc4 on unix, I am trying to process files from a specific directory, without knowing the file names. I want to process each files in there one by one and delete them after being processed, any trics or ideas? Thanks.

Hi,

You can do ls command for the directory and store the output to a text file and then read each line of that output file using seq.* functions. Once closed, use seq.unlink() or rm command to remove the file.

Or, go for dir.* functions. Which includes dir.open() followed by dir.entry() and then dir.close() Take a look - > Link (http://www.baanboard.com/programmers_manual_baanerp_help_functions_directory_file_operations_dir_entry)

You should be able to use dir.open() (http://www.baanboard.com/programmers_manual_baanerp_help_functions_directory_file_operations_dir_open), dir.entry() (http://www.baanboard.com/programmers_manual_baanerp_help_functions_directory_file_operations_dir_entry) and dir.close() (http://www.baanboard.com/programmers_manual_baanerp_help_functions_directory_file_operations_dir_close)functions.


fd=dir.open(directory.name)
|Get first file name
filename = dir.entry(fd, TDIR, rt, size, mode)

while (not isspace(filename))
do.something.with.file(filename)
|Get next file name
filename=dir.entry(fd, TDIR, rt, size, mode)
endwhile
dir.close(fd)

The dir.* functions are easy to use. The only thing to remember: You get the directory entries in the order they stored in the directory. On unix boxes, you can try this:

mkdir /tmp/foo; cd /tmp/foo; >A; >B; >C; rm A; >D

=> You will get D, B, C.

If you have a requiremend to process files in the order they were created, (and you are on Unix) you can use fd=pipe.open("/bin/ls -tr ") and then seq.gets(..., fd), too.

Regards
Günther